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x\left(-x^{2}-x+6\right)
Factor out x.
a+b=-1 ab=-6=-6
Consider -x^{2}-x+6. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+6. To find a and b, set up a system to be solved.
1,-6 2,-3
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -6.
1-6=-5 2-3=-1
Calculate the sum for each pair.
a=2 b=-3
The solution is the pair that gives sum -1.
\left(-x^{2}+2x\right)+\left(-3x+6\right)
Rewrite -x^{2}-x+6 as \left(-x^{2}+2x\right)+\left(-3x+6\right).
x\left(-x+2\right)+3\left(-x+2\right)
Factor out x in the first and 3 in the second group.
\left(-x+2\right)\left(x+3\right)
Factor out common term -x+2 by using distributive property.
x\left(-x+2\right)\left(x+3\right)
Rewrite the complete factored expression.