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x\left(-x^{2}+2x-1\right)
Factor out x.
a+b=2 ab=-\left(-1\right)=1
Consider -x^{2}+2x-1. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx-1. To find a and b, set up a system to be solved.
a=1 b=1
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. The only such pair is the system solution.
\left(-x^{2}+x\right)+\left(x-1\right)
Rewrite -x^{2}+2x-1 as \left(-x^{2}+x\right)+\left(x-1\right).
-x\left(x-1\right)+x-1
Factor out -x in -x^{2}+x.
\left(x-1\right)\left(-x+1\right)
Factor out common term x-1 by using distributive property.
x\left(x-1\right)\left(-x+1\right)
Rewrite the complete factored expression.