Skip to main content
Solve for x
Tick mark Image
Graph

Similar Problems from Web Search

Share

x^{2}+2x-3<0
Multiply the inequality by -1 to make the coefficient of the highest power in -x^{2}-2x+3 positive. Since -1 is negative, the inequality direction is changed.
x^{2}+2x-3=0
To solve the inequality, factor the left hand side. Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-2±\sqrt{2^{2}-4\times 1\left(-3\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 1 for a, 2 for b, and -3 for c in the quadratic formula.
x=\frac{-2±4}{2}
Do the calculations.
x=1 x=-3
Solve the equation x=\frac{-2±4}{2} when ± is plus and when ± is minus.
\left(x-1\right)\left(x+3\right)<0
Rewrite the inequality by using the obtained solutions.
x-1>0 x+3<0
For the product to be negative, x-1 and x+3 have to be of the opposite signs. Consider the case when x-1 is positive and x+3 is negative.
x\in \emptyset
This is false for any x.
x+3>0 x-1<0
Consider the case when x+3 is positive and x-1 is negative.
x\in \left(-3,1\right)
The solution satisfying both inequalities is x\in \left(-3,1\right).
x\in \left(-3,1\right)
The final solution is the union of the obtained solutions.