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a+b=9 ab=-70=-70
Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+70. To find a and b, set up a system to be solved.
-1,70 -2,35 -5,14 -7,10
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -70.
-1+70=69 -2+35=33 -5+14=9 -7+10=3
Calculate the sum for each pair.
a=14 b=-5
The solution is the pair that gives sum 9.
\left(-x^{2}+14x\right)+\left(-5x+70\right)
Rewrite -x^{2}+9x+70 as \left(-x^{2}+14x\right)+\left(-5x+70\right).
-x\left(x-14\right)-5\left(x-14\right)
Factor out -x in the first and -5 in the second group.
\left(x-14\right)\left(-x-5\right)
Factor out common term x-14 by using distributive property.
-x^{2}+9x+70=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-9±\sqrt{9^{2}-4\left(-1\right)\times 70}}{2\left(-1\right)}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-9±\sqrt{81-4\left(-1\right)\times 70}}{2\left(-1\right)}
Square 9.
x=\frac{-9±\sqrt{81+4\times 70}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-9±\sqrt{81+280}}{2\left(-1\right)}
Multiply 4 times 70.
x=\frac{-9±\sqrt{361}}{2\left(-1\right)}
Add 81 to 280.
x=\frac{-9±19}{2\left(-1\right)}
Take the square root of 361.
x=\frac{-9±19}{-2}
Multiply 2 times -1.
x=\frac{10}{-2}
Now solve the equation x=\frac{-9±19}{-2} when ± is plus. Add -9 to 19.
x=-5
Divide 10 by -2.
x=-\frac{28}{-2}
Now solve the equation x=\frac{-9±19}{-2} when ± is minus. Subtract 19 from -9.
x=14
Divide -28 by -2.
-x^{2}+9x+70=-\left(x-\left(-5\right)\right)\left(x-14\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -5 for x_{1} and 14 for x_{2}.
-x^{2}+9x+70=-\left(x+5\right)\left(x-14\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.
x ^ 2 -9x -70 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 9 rs = -70
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = \frac{9}{2} - u s = \frac{9}{2} + u
Two numbers r and s sum up to 9 exactly when the average of the two numbers is \frac{1}{2}*9 = \frac{9}{2}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(\frac{9}{2} - u) (\frac{9}{2} + u) = -70
To solve for unknown quantity u, substitute these in the product equation rs = -70
\frac{81}{4} - u^2 = -70
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = -70-\frac{81}{4} = -\frac{361}{4}
Simplify the expression by subtracting \frac{81}{4} on both sides
u^2 = \frac{361}{4} u = \pm\sqrt{\frac{361}{4}} = \pm \frac{19}{2}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =\frac{9}{2} - \frac{19}{2} = -5 s = \frac{9}{2} + \frac{19}{2} = 14
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.