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-x^{2}+20x-94=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-20±\sqrt{20^{2}-4\left(-1\right)\left(-94\right)}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 20 for b, and -94 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-20±\sqrt{400-4\left(-1\right)\left(-94\right)}}{2\left(-1\right)}
Square 20.
x=\frac{-20±\sqrt{400+4\left(-94\right)}}{2\left(-1\right)}
Multiply -4 times -1.
x=\frac{-20±\sqrt{400-376}}{2\left(-1\right)}
Multiply 4 times -94.
x=\frac{-20±\sqrt{24}}{2\left(-1\right)}
Add 400 to -376.
x=\frac{-20±2\sqrt{6}}{2\left(-1\right)}
Take the square root of 24.
x=\frac{-20±2\sqrt{6}}{-2}
Multiply 2 times -1.
x=\frac{2\sqrt{6}-20}{-2}
Now solve the equation x=\frac{-20±2\sqrt{6}}{-2} when ± is plus. Add -20 to 2\sqrt{6}.
x=10-\sqrt{6}
Divide -20+2\sqrt{6} by -2.
x=\frac{-2\sqrt{6}-20}{-2}
Now solve the equation x=\frac{-20±2\sqrt{6}}{-2} when ± is minus. Subtract 2\sqrt{6} from -20.
x=\sqrt{6}+10
Divide -20-2\sqrt{6} by -2.
x=10-\sqrt{6} x=\sqrt{6}+10
The equation is now solved.
-x^{2}+20x-94=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-x^{2}+20x-94-\left(-94\right)=-\left(-94\right)
Add 94 to both sides of the equation.
-x^{2}+20x=-\left(-94\right)
Subtracting -94 from itself leaves 0.
-x^{2}+20x=94
Subtract -94 from 0.
\frac{-x^{2}+20x}{-1}=\frac{94}{-1}
Divide both sides by -1.
x^{2}+\frac{20}{-1}x=\frac{94}{-1}
Dividing by -1 undoes the multiplication by -1.
x^{2}-20x=\frac{94}{-1}
Divide 20 by -1.
x^{2}-20x=-94
Divide 94 by -1.
x^{2}-20x+\left(-10\right)^{2}=-94+\left(-10\right)^{2}
Divide -20, the coefficient of the x term, by 2 to get -10. Then add the square of -10 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}-20x+100=-94+100
Square -10.
x^{2}-20x+100=6
Add -94 to 100.
\left(x-10\right)^{2}=6
Factor x^{2}-20x+100. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-10\right)^{2}}=\sqrt{6}
Take the square root of both sides of the equation.
x-10=\sqrt{6} x-10=-\sqrt{6}
Simplify.
x=\sqrt{6}+10 x=10-\sqrt{6}
Add 10 to both sides of the equation.
x ^ 2 -20x +94 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = 20 rs = 94
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = 10 - u s = 10 + u
Two numbers r and s sum up to 20 exactly when the average of the two numbers is \frac{1}{2}*20 = 10. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(10 - u) (10 + u) = 94
To solve for unknown quantity u, substitute these in the product equation rs = 94
100 - u^2 = 94
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 94-100 = -6
Simplify the expression by subtracting 100 on both sides
u^2 = 6 u = \pm\sqrt{6} = \pm \sqrt{6}
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =10 - \sqrt{6} = 7.551 s = 10 + \sqrt{6} = 12.449
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.