Solve for x
x=3\left(y-3\right)
Solve for y
y=\frac{x+9}{3}
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-x=9-3y
Subtract 3y from both sides.
\frac{-x}{-1}=\frac{9-3y}{-1}
Divide both sides by -1.
x=\frac{9-3y}{-1}
Dividing by -1 undoes the multiplication by -1.
x=3y-9
Divide 9-3y by -1.
3y=9+x
Add x to both sides.
3y=x+9
The equation is in standard form.
\frac{3y}{3}=\frac{x+9}{3}
Divide both sides by 3.
y=\frac{x+9}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{x}{3}+3
Divide 9+x by 3.
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