Skip to main content
Solve for n
Tick mark Image

Similar Problems from Web Search

Share

-n^{2}-11n=0
Subtract 11n from both sides.
n=\frac{-\left(-11\right)±\sqrt{\left(-11\right)^{2}}}{2\left(-1\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, -11 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
n=\frac{-\left(-11\right)±11}{2\left(-1\right)}
Take the square root of \left(-11\right)^{2}.
n=\frac{11±11}{2\left(-1\right)}
The opposite of -11 is 11.
n=\frac{11±11}{-2}
Multiply 2 times -1.
n=\frac{22}{-2}
Now solve the equation n=\frac{11±11}{-2} when ± is plus. Add 11 to 11.
n=-11
Divide 22 by -2.
n=\frac{0}{-2}
Now solve the equation n=\frac{11±11}{-2} when ± is minus. Subtract 11 from 11.
n=0
Divide 0 by -2.
n=-11 n=0
The equation is now solved.
-n^{2}-11n=0
Subtract 11n from both sides.
\frac{-n^{2}-11n}{-1}=\frac{0}{-1}
Divide both sides by -1.
n^{2}+\left(-\frac{11}{-1}\right)n=\frac{0}{-1}
Dividing by -1 undoes the multiplication by -1.
n^{2}+11n=\frac{0}{-1}
Divide -11 by -1.
n^{2}+11n=0
Divide 0 by -1.
n^{2}+11n+\left(\frac{11}{2}\right)^{2}=\left(\frac{11}{2}\right)^{2}
Divide 11, the coefficient of the x term, by 2 to get \frac{11}{2}. Then add the square of \frac{11}{2} to both sides of the equation. This step makes the left hand side of the equation a perfect square.
n^{2}+11n+\frac{121}{4}=\frac{121}{4}
Square \frac{11}{2} by squaring both the numerator and the denominator of the fraction.
\left(n+\frac{11}{2}\right)^{2}=\frac{121}{4}
Factor n^{2}+11n+\frac{121}{4}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(n+\frac{11}{2}\right)^{2}}=\sqrt{\frac{121}{4}}
Take the square root of both sides of the equation.
n+\frac{11}{2}=\frac{11}{2} n+\frac{11}{2}=-\frac{11}{2}
Simplify.
n=0 n=-11
Subtract \frac{11}{2} from both sides of the equation.