Solve -n^2+(0n+1)=0

$$- n ^ { 2 } + ( 0 n + 1 ) = 0$$

Solve for n

$$n=1$$

$$n=-1$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$-n^{2}+1=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute -1 for a, 0 for b, and 1 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$n=\frac{0±\sqrt{0^{2}-4\left(-1\right)}}{2\left(-1\right)}$$

Square 0.

$$n=\frac{0±\sqrt{-4\left(-1\right)}}{2\left(-1\right)}$$

Multiply -4 times -1.

$$n=\frac{0±\sqrt{4}}{2\left(-1\right)}$$

Take the square root of 4.

$$n=\frac{0±2}{2\left(-1\right)}$$

Multiply 2 times -1.

$$n=\frac{0±2}{-2}$$

Now solve the equation n=\frac{0±2}{-2} when ± is plus. Divide 2 by -2.

$$n=-1$$

Now solve the equation n=\frac{0±2}{-2} when ± is minus. Divide -2 by -2.

$$n=1$$

The equation is now solved.

$$n=-1 n=1$$