Solve -h(10)=x+1/(2x-6)(x-1)=

$$- h ( 10 ) = \frac { x + 1 } { ( 2 x - 6 ) ( x - 1 ) } =$$

Solve for h

$$h=\frac{x+1}{20\left(1-x\right)\left(x-3\right)}$$

$$x\neq 3\text{ and }x\neq 1$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2\left(x-3\right)\left(x-1\right).

$$\left(-h\right)\times 10\times 2\left(x-3\right)\left(x-1\right)=x+1$$

Multiply 10 and 2 to get 20.

$$\left(-h\right)\times 20\left(x-3\right)\left(x-1\right)=x+1$$

Use the distributive property to multiply \left(-h\right)\times 20 by x-3.

$$\left(20\left(-h\right)x-3\left(-h\right)\times 20\right)\left(x-1\right)=x+1$$

Multiply -3 and 20 to get -60.

$$\left(20\left(-h\right)x-60\left(-h\right)\right)\left(x-1\right)=x+1$$

Multiply -60 and -1 to get 60.

$$\left(20\left(-h\right)x+60h\right)\left(x-1\right)=x+1$$

Use the distributive property to multiply 20\left(-h\right)x+60h by x-1.

$$20\left(-h\right)x^{2}-20\left(-h\right)x+60hx-60h=x+1$$

Multiply -20 and -1 to get 20.

$$20\left(-h\right)x^{2}+20hx+60hx-60h=x+1$$

Combine 20hx and 60hx to get 80hx.

$$20\left(-h\right)x^{2}+80hx-60h=x+1$$

Multiply 20 and -1 to get -20.

$$-20hx^{2}+80hx-60h=x+1$$

Combine all terms containing h.

$$\left(-20x^{2}+80x-60\right)h=x+1$$

Divide both sides by -20x^{2}+80x-60.

$$\frac{\left(-20x^{2}+80x-60\right)h}{-20x^{2}+80x-60}=\frac{x+1}{-20x^{2}+80x-60}$$

Dividing by -20x^{2}+80x-60 undoes the multiplication by -20x^{2}+80x-60.

$$h=\frac{x+1}{-20x^{2}+80x-60}$$

Divide x+1 by -20x^{2}+80x-60.

$$h=\frac{x+1}{20\left(1-x\right)\left(x-3\right)}$$

Solve for x (complex solution)

$$\left\{\begin{matrix}x=-\frac{\sqrt{1600h^{2}-240h+1}-80h+1}{40h}\text{; }x=-\frac{-\sqrt{1600h^{2}-240h+1}-80h+1}{40h}\text{, }&h\neq 0\\x=-1\text{, }&h=0\end{matrix}\right.$$

Solve for x

$$\left\{\begin{matrix}x=-\frac{\sqrt{1600h^{2}-240h+1}-80h+1}{40h}\text{; }x=-\frac{-\sqrt{1600h^{2}-240h+1}-80h+1}{40h}\text{, }&\left(h\neq 0\text{ and }h\leq -\frac{\sqrt{2}}{20}+\frac{3}{40}\right)\text{ or }h\geq \frac{\sqrt{2}}{20}+\frac{3}{40}\\x=-1\text{, }&h=0\end{matrix}\right.$$