Solve -f(x)=2xquad[1,3]

$$- f ( x ) = 2 x \quad [ 1,3 ]$$

Solve for f

$$\left\{\begin{matrix}\\f=-2,6\text{, }&\text{unconditionally}\\f\in \mathrm{R}\text{, }&x=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 2 and 1,3 to get 2,6.

$$\left(-f\right)x=2,6x$$

Reorder the terms.

$$-fx=2,6x$$

The equation is in standard form.

$$\left(-x\right)f=\frac{13x}{5}$$

Divide both sides by -x.

$$\frac{\left(-x\right)f}{-x}=\frac{13x}{5\left(-x\right)}$$

Dividing by -x undoes the multiplication by -x.

$$f=\frac{13x}{5\left(-x\right)}$$

Divide \frac{13x}{5} by -x.

$$f=-\frac{13}{5}$$

Solve for x

$$\left\{\begin{matrix}\\x=0\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&f=-\frac{13}{5}\end{matrix}\right.$$

Steps for Solving Linear Equation

Multiply 2 and 1,3 to get 2,6.

$$\left(-f\right)x=2,6x$$

Subtract 2,6x from both sides.

$$\left(-f\right)x-2,6x=0$$

Reorder the terms.

$$-fx-2,6x=0$$

Combine all terms containing x.

$$\left(-f-2,6\right)x=0$$

Divide 0 by -2,6-f.

$$x=0$$