Solve for f
f=-\frac{1}{3}+\frac{7}{3x}
x\neq 0
Solve for x
x=\frac{7}{3f+1}
f\neq -\frac{1}{3}
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3\left(-f\right)x=x-7
Multiply both sides of the equation by 3.
-3fx=x-7
Multiply 3 and -1 to get -3.
\left(-3x\right)f=x-7
The equation is in standard form.
\frac{\left(-3x\right)f}{-3x}=\frac{x-7}{-3x}
Divide both sides by -3x.
f=\frac{x-7}{-3x}
Dividing by -3x undoes the multiplication by -3x.
f=-\frac{1}{3}+\frac{7}{3x}
Divide x-7 by -3x.
3\left(-f\right)x=x-7
Multiply both sides of the equation by 3.
3\left(-f\right)x-x=-7
Subtract x from both sides.
-3fx-x=-7
Multiply 3 and -1 to get -3.
\left(-3f-1\right)x=-7
Combine all terms containing x.
\frac{\left(-3f-1\right)x}{-3f-1}=-\frac{7}{-3f-1}
Divide both sides by -3f-1.
x=-\frac{7}{-3f-1}
Dividing by -3f-1 undoes the multiplication by -3f-1.
x=\frac{7}{3f+1}
Divide -7 by -3f-1.
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