Solve -a+4a^2

$$- a + 4 a ^ { 2 }$$

Factor

$$a\left(4a-1\right)$$

Solution Steps

Factor out a.

$$a\left(-1+4a\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$4a^{2}-a=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$a=\frac{-\left(-1\right)±\sqrt{1}}{2\times 4}$$

Take the square root of 1.

$$a=\frac{-\left(-1\right)±1}{2\times 4}$$

The opposite of -1 is 1.

$$a=\frac{1±1}{2\times 4}$$

Multiply 2 times 4.

$$a=\frac{1±1}{8}$$

Now solve the equation a=\frac{1±1}{8} when ± is plus. Add 1 to 1.

$$a=\frac{2}{8}$$

Reduce the fraction \frac{2}{8} to lowest terms by extracting and canceling out 2.

$$a=\frac{1}{4}$$

Now solve the equation a=\frac{1±1}{8} when ± is minus. Subtract 1 from 1.

$$a=\frac{0}{8}$$

Divide 0 by 8.

$$a=0$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute \frac{1}{4} for x_{1} and 0 for x_{2}.

$$4a^{2}-a=4\left(a-\frac{1}{4}\right)a$$

Subtract \frac{1}{4} from a by finding a common denominator and subtracting the numerators. Then reduce the fraction to lowest terms if possible.

$$4a^{2}-a=4\times \frac{4a-1}{4}a$$

Cancel out 4, the greatest common factor in 4 and 4.

$$4a^{2}-a=\left(4a-1\right)a$$

Evaluate

$$a\left(4a-1\right)$$