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Solve for I
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\left(-I\right)\times 10+6-8-12=0
Multiply 1 and 8 to get 8.
\left(-I\right)\times 10-2-12=0
Subtract 8 from 6 to get -2.
\left(-I\right)\times 10-14=0
Subtract 12 from -2 to get -14.
\left(-I\right)\times 10=14
Add 14 to both sides. Anything plus zero gives itself.
-I=\frac{14}{10}
Divide both sides by 10.
-I=\frac{7}{5}
Reduce the fraction \frac{14}{10} to lowest terms by extracting and canceling out 2.
I=-\frac{7}{5}
Multiply both sides by -1.