Solve -98+99-7*34+3/4*25+x26/43/13

$$- 98 + 99 - 7 \times 34 + \frac { 3 } { 4 } \times 25 + x \frac { 26 } { 4 } \frac { 3 } { 13 }$$

Evaluate

$$\frac{3x}{2}-\frac{873}{4}$$

Solution Steps

Add -98 and 99 to get 1.

$$1-7\times 34+\frac{3}{4}\times 25+x\times \frac{26}{4}\times \frac{3}{13}$$

Multiply 7 and 34 to get 238.

$$1-238+\frac{3}{4}\times 25+x\times \frac{26}{4}\times \frac{3}{13}$$

Subtract 238 from 1 to get -237.

$$-237+\frac{3}{4}\times 25+x\times \frac{26}{4}\times \frac{3}{13}$$

Express \frac{3}{4}\times 25 as a single fraction.

$$-237+\frac{3\times 25}{4}+x\times \frac{26}{4}\times \frac{3}{13}$$

Multiply 3 and 25 to get 75.

$$-237+\frac{75}{4}+x\times \frac{26}{4}\times \frac{3}{13}$$

Convert -237 to fraction -\frac{948}{4}.

$$-\frac{948}{4}+\frac{75}{4}+x\times \frac{26}{4}\times \frac{3}{13}$$

Since -\frac{948}{4} and \frac{75}{4} have the same denominator, add them by adding their numerators.

$$\frac{-948+75}{4}+x\times \frac{26}{4}\times \frac{3}{13}$$

Add -948 and 75 to get -873.

$$-\frac{873}{4}+x\times \frac{26}{4}\times \frac{3}{13}$$

Reduce the fraction \frac{26}{4} to lowest terms by extracting and canceling out 2.

$$-\frac{873}{4}+x\times \frac{13}{2}\times \frac{3}{13}$$

Multiply \frac{13}{2} times \frac{3}{13} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{873}{4}+x\times \frac{13\times 3}{2\times 13}$$

Cancel out 13 in both numerator and denominator.

$$-\frac{873}{4}+x\times \frac{3}{2}$$

Factor

$$\frac{3\left(2x-291\right)}{4}$$

Solution Steps

Factor out \frac{1}{4}.

$$\frac{-873+6x}{4}$$

Consider -392+396-952+75+6x. Multiply and combine like terms.

$$6x-873$$

Consider 6x-873. Factor out 3.

$$3\left(2x-291\right)$$

Rewrite the complete factored expression.

$$\frac{3\left(2x-291\right)}{4}$$