Solve for x
x=\frac{2\left(y-3\right)}{3}
Solve for y
y=\frac{3\left(x+2\right)}{2}
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-9x=18-6y
Subtract 6y from both sides.
\frac{-9x}{-9}=\frac{18-6y}{-9}
Divide both sides by -9.
x=\frac{18-6y}{-9}
Dividing by -9 undoes the multiplication by -9.
x=\frac{2y}{3}-2
Divide 18-6y by -9.
6y=18+9x
Add 9x to both sides.
6y=9x+18
The equation is in standard form.
\frac{6y}{6}=\frac{9x+18}{6}
Divide both sides by 6.
y=\frac{9x+18}{6}
Dividing by 6 undoes the multiplication by 6.
y=\frac{3x}{2}+3
Divide 18+9x by 6.
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