Solve for x
x=\frac{y+9}{3}
Solve for y
y=3\left(x-3\right)
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-9x=-27-3y
Subtract 3y from both sides.
-9x=-3y-27
The equation is in standard form.
\frac{-9x}{-9}=\frac{-3y-27}{-9}
Divide both sides by -9.
x=\frac{-3y-27}{-9}
Dividing by -9 undoes the multiplication by -9.
x=\frac{y}{3}+3
Divide -27-3y by -9.
3y=-27+9x
Add 9x to both sides.
3y=9x-27
The equation is in standard form.
\frac{3y}{3}=\frac{9x-27}{3}
Divide both sides by 3.
y=\frac{9x-27}{3}
Dividing by 3 undoes the multiplication by 3.
y=3x-9
Divide -27+9x by 3.
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