Solve -9(z+2)+4(4z-4)=6(z-5)+10

$$- 9 ( z + 2 ) + 4 ( 4 z - 4 ) = 6 ( z - 5 ) + 10$$

Solve for z

$$z=14$$

Steps for Solving Linear Equation

Use the distributive property to multiply -9 by z+2.

$$-9z-18+4\left(4z-4\right)=6\left(z-5\right)+10$$

Use the distributive property to multiply 4 by 4z-4.

$$-9z-18+16z-16=6\left(z-5\right)+10$$

Combine -9z and 16z to get 7z.

$$7z-18-16=6\left(z-5\right)+10$$

Subtract 16 from -18 to get -34.

$$7z-34=6\left(z-5\right)+10$$

Use the distributive property to multiply 6 by z-5.

$$7z-34=6z-30+10$$

Add -30 and 10 to get -20.

$$7z-34=6z-20$$

Subtract 6z from both sides.

$$7z-34-6z=-20$$

Combine 7z and -6z to get z.

$$z-34=-20$$

Add 34 to both sides.

$$z=-20+34$$

Add -20 and 34 to get 14.

$$z=14$$