Solve -9(-2x-3)geq4(2x-3)

$$- 9 ( - 2 x - 3 ) \geq 4 ( 2 x - 3 )$$

Solve for x

$$x\geq -\frac{39}{10}$$

Solution Steps

Use the distributive property to multiply -9 by -2x-3.

$$18x+27\geq 4\left(2x-3\right)$$

Use the distributive property to multiply 4 by 2x-3.

$$18x+27\geq 8x-12$$

Subtract 8x from both sides.

$$18x+27-8x\geq -12$$

Combine 18x and -8x to get 10x.

$$10x+27\geq -12$$

Subtract 27 from both sides.

$$10x\geq -12-27$$

Subtract 27 from -12 to get -39.

$$10x\geq -39$$

Divide both sides by 10. Since 10 is positive, the inequality direction remains the same.

$$x\geq -\frac{39}{10}$$