Solve -9*(-1/2+1/6)-8div(-2)^2+12/5

$$- 9 \times ( - \frac { 1 } { 2 } + \frac { 1 } { 6 } ) - 8 \div ( - 2 ) ^ { 2 } + 1 \frac { 2 } { 5 }$$

Evaluate

$$\frac{12}{5}=2.4$$

Solution Steps

Least common multiple of 2 and 6 is 6. Convert -\frac{1}{2} and \frac{1}{6} to fractions with denominator 6.

$$-9\left(-\frac{3}{6}+\frac{1}{6}\right)-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Since -\frac{3}{6} and \frac{1}{6} have the same denominator, add them by adding their numerators.

$$-9\times \frac{-3+1}{6}-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Add -3 and 1 to get -2.

$$-9\times \frac{-2}{6}-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Reduce the fraction \frac{-2}{6} to lowest terms by extracting and canceling out 2.

$$-9\left(-\frac{1}{3}\right)-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Express -9\left(-\frac{1}{3}\right) as a single fraction.

$$\frac{-9\left(-1\right)}{3}-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Multiply -9 and -1 to get 9.

$$\frac{9}{3}-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Divide 9 by 3 to get 3.

$$3-\frac{8}{\left(-2\right)^{2}}+\frac{1\times 5+2}{5}$$

Calculate -2 to the power of 2 and get 4.

$$3-\frac{8}{4}+\frac{1\times 5+2}{5}$$

Divide 8 by 4 to get 2.

$$3-2+\frac{1\times 5+2}{5}$$

Subtract 2 from 3 to get 1.

$$1+\frac{1\times 5+2}{5}$$

Multiply 1 and 5 to get 5.

$$1+\frac{5+2}{5}$$

Add 5 and 2 to get 7.

$$1+\frac{7}{5}$$

Convert 1 to fraction \frac{5}{5}.

$$\frac{5}{5}+\frac{7}{5}$$

Since \frac{5}{5} and \frac{7}{5} have the same denominator, add them by adding their numerators.

$$\frac{5+7}{5}$$

Add 5 and 7 to get 12.

$$\frac{12}{5}$$

Factor

$$\frac{2 ^ {2} \cdot 3}{5} = 2\frac{2}{5} = 2.4$$