Solve -9quad80(1+x)^2=135.2

$$- 9 \quad 80 ( 1 + x ) ^ { 2 } = 135.2$$

Solve for x (complex solution)

$$x=-1-\frac{13}{30}i\approx -1-0.433333333i$$

$$x=-1+\frac{13}{30}i\approx -1+0.433333333i$$

Steps by Finding Square Root

Dividing by -720 undoes the multiplication by -720.

$$\left(x+1\right)^{2}=\frac{135.2}{-720}$$

Divide 135.2 by -720.

$$\left(x+1\right)^{2}=-\frac{169}{900}$$

Take the square root of both sides of the equation.

$$x+1=\frac{13}{30}i x+1=-\frac{13}{30}i$$

Subtract 1 from both sides of the equation.

$$x+1-1=\frac{13}{30}i-1 x+1-1=-\frac{13}{30}i-1$$

Subtracting 1 from itself leaves 0.

$$x=\frac{13}{30}i-1 x=-\frac{13}{30}i-1$$

Subtract 1 from \frac{13}{30}i.

$$x=-1+\frac{13}{30}i$$

Subtract 1 from -\frac{13}{30}i.

$$x=-1-\frac{13}{30}i$$

The equation is now solved.

$$x=-1+\frac{13}{30}i x=-1-\frac{13}{30}i$$