Solve -9*n/3n-3n/n*3n/n-3n

$$- 9 \cdot \frac { n } { 3 n } - \frac { 3 n } { n } \times \frac { 3 n } { n - 3 n }$$

Evaluate

$$\frac{3}{2}=1.5$$

Solution Steps

Cancel out n in both numerator and denominator.

$$-9\times \frac{1}{3}-\frac{3n}{n}\times \frac{3n}{n-3n}$$

Multiply -9 and \frac{1}{3} to get \frac{-9}{3}.

$$\frac{-9}{3}-\frac{3n}{n}\times \frac{3n}{n-3n}$$

Divide -9 by 3 to get -3.

$$-3-\frac{3n}{n}\times \frac{3n}{n-3n}$$

Cancel out n in both numerator and denominator.

$$-3-3\times \frac{3n}{n-3n}$$

Combine n and -3n to get -2n.

$$-3-3\times \frac{3n}{-2n}$$

Cancel out n in both numerator and denominator.

$$-3-3\times \frac{3}{-2}$$

Fraction \frac{3}{-2} can be rewritten as -\frac{3}{2} by extracting the negative sign.

$$-3-3\left(-\frac{3}{2}\right)$$

Express 3\left(-\frac{3}{2}\right) as a single fraction.

$$-3-\frac{3\left(-3\right)}{2}$$

Multiply 3 and -3 to get -9.

$$-3-\frac{-9}{2}$$

Fraction \frac{-9}{2} can be rewritten as -\frac{9}{2} by extracting the negative sign.

$$-3-\left(-\frac{9}{2}\right)$$

The opposite of -\frac{9}{2} is \frac{9}{2}.

$$-3+\frac{9}{2}$$

Convert -3 to fraction -\frac{6}{2}.

$$-\frac{6}{2}+\frac{9}{2}$$

Since -\frac{6}{2} and \frac{9}{2} have the same denominator, add them by adding their numerators.

$$\frac{-6+9}{2}$$

Add -6 and 9 to get 3.

$$\frac{3}{2}$$

Factor

$$\frac{3}{2} = 1\frac{1}{2} = 1.5$$