Solve for x
x=-\frac{y}{4}+\frac{1}{8}
Solve for y
y=\frac{1}{2}-4x
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-8x=-1+2y
Add 2y to both sides.
-8x=2y-1
The equation is in standard form.
\frac{-8x}{-8}=\frac{2y-1}{-8}
Divide both sides by -8.
x=\frac{2y-1}{-8}
Dividing by -8 undoes the multiplication by -8.
x=-\frac{y}{4}+\frac{1}{8}
Divide -1+2y by -8.
-2y=-1+8x
Add 8x to both sides.
-2y=8x-1
The equation is in standard form.
\frac{-2y}{-2}=\frac{8x-1}{-2}
Divide both sides by -2.
y=\frac{8x-1}{-2}
Dividing by -2 undoes the multiplication by -2.
y=\frac{1}{2}-4x
Divide -1+8x by -2.
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