Solve -8[(-18+6*2):3+(-20:5+2):(-2)]=

$$- 8 [ ( - 18 + 6 \cdot 2 ) : 3 + ( - 20 : 5 + 2 ) : ( - 2 ) ] =$$

Evaluate

$$8$$

Solution Steps

Multiply 6 and 2 to get 12.

$$-8\left(\frac{-18+12}{3}+\frac{\frac{-20}{5}+2}{-2}\right)$$

Add -18 and 12 to get -6.

$$-8\left(\frac{-6}{3}+\frac{\frac{-20}{5}+2}{-2}\right)$$

Divide -6 by 3 to get -2.

$$-8\left(-2+\frac{\frac{-20}{5}+2}{-2}\right)$$

Divide -20 by 5 to get -4.

$$-8\left(-2+\frac{-4+2}{-2}\right)$$

Add -4 and 2 to get -2.

$$-8\left(-2+\frac{-2}{-2}\right)$$

Divide -2 by -2 to get 1.

$$-8\left(-2+1\right)$$

Add -2 and 1 to get -1.

$$-8\left(-1\right)$$

Multiply -8 and -1 to get 8.

$$8$$

Factor

$$2^{3}$$