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-12x^{2}+2x+4
Multiply and combine like terms.
2\left(-6x^{2}+x+2\right)
Factor out 2.
a+b=1 ab=-6\times 2=-12
Consider -6x^{2}+x+2. Factor the expression by grouping. First, the expression needs to be rewritten as -6x^{2}+ax+bx+2. To find a and b, set up a system to be solved.
-1,12 -2,6 -3,4
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -12.
-1+12=11 -2+6=4 -3+4=1
Calculate the sum for each pair.
a=4 b=-3
The solution is the pair that gives sum 1.
\left(-6x^{2}+4x\right)+\left(-3x+2\right)
Rewrite -6x^{2}+x+2 as \left(-6x^{2}+4x\right)+\left(-3x+2\right).
2x\left(-3x+2\right)-3x+2
Factor out 2x in -6x^{2}+4x.
\left(-3x+2\right)\left(2x+1\right)
Factor out common term -3x+2 by using distributive property.
2\left(-3x+2\right)\left(2x+1\right)
Rewrite the complete factored expression.
-12x^{2}+2x+4
Combine -7x^{2} and -5x^{2} to get -12x^{2}.