Solve -71/20quad-724/25quad34/40quad17/25

$$- 7 \frac { 1 } { 20 } \quad - 7 \frac { 24 } { 25 } \quad \frac { 34 } { 40 } \quad \frac { 17 } { 25 }$$

Evaluate

$$-\frac{36409}{3125}=-11.65088$$

Solution Steps

Multiply 7 and 20 to get 140.

$$-\frac{140+1}{20}-\frac{7\times 25+24}{25}\times \frac{34}{40}\times \frac{17}{25}$$

Add 140 and 1 to get 141.

$$-\frac{141}{20}-\frac{7\times 25+24}{25}\times \frac{34}{40}\times \frac{17}{25}$$

Multiply 7 and 25 to get 175.

$$-\frac{141}{20}-\frac{175+24}{25}\times \frac{34}{40}\times \frac{17}{25}$$

Add 175 and 24 to get 199.

$$-\frac{141}{20}-\frac{199}{25}\times \frac{34}{40}\times \frac{17}{25}$$

Reduce the fraction \frac{34}{40} to lowest terms by extracting and canceling out 2.

$$-\frac{141}{20}-\frac{199}{25}\times \frac{17}{20}\times \frac{17}{25}$$

Multiply \frac{199}{25} times \frac{17}{20} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{141}{20}-\frac{199\times 17}{25\times 20}\times \frac{17}{25}$$

Do the multiplications in the fraction \frac{199\times 17}{25\times 20}.

$$-\frac{141}{20}-\frac{3383}{500}\times \frac{17}{25}$$

Multiply \frac{3383}{500} times \frac{17}{25} by multiplying numerator times numerator and denominator times denominator.

$$-\frac{141}{20}-\frac{3383\times 17}{500\times 25}$$

Do the multiplications in the fraction \frac{3383\times 17}{500\times 25}.

$$-\frac{141}{20}-\frac{57511}{12500}$$

Least common multiple of 20 and 12500 is 12500. Convert -\frac{141}{20} and \frac{57511}{12500} to fractions with denominator 12500.

$$-\frac{88125}{12500}-\frac{57511}{12500}$$

Since -\frac{88125}{12500} and \frac{57511}{12500} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-88125-57511}{12500}$$

Subtract 57511 from -88125 to get -145636.

$$\frac{-145636}{12500}$$

Reduce the fraction \frac{-145636}{12500} to lowest terms by extracting and canceling out 4.

$$-\frac{36409}{3125}$$

Factor

$$-\frac{36409}{3125} = -11\frac{2034}{3125} = -11.65088$$