Solve -7^2+(7-4)^3=7^2+3^3

$$- 7 ^ { 2 } + ( 7 - 4 ) ^ { 3 } = 7 ^ { 2 } + 3 ^ { 3 }$$

Verify

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$-49+\left(7-4\right)^{3}=7^{2}+3^{3}$$

Subtract 4 from 7 to get 3.

$$-49+3^{3}=7^{2}+3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$-49+27=7^{2}+3^{3}$$

Add -49 and 27 to get -22.

$$-22=7^{2}+3^{3}$$

Calculate 7 to the power of 2 and get 49.

$$-22=49+3^{3}$$

Calculate 3 to the power of 3 and get 27.

$$-22=49+27$$

Add 49 and 27 to get 76.

$$-22=76$$

Compare -22 and 76.

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