Solve for a
a=\frac{7-2z}{3}
Solve for z
z=\frac{7-3a}{2}
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3a=-2z+7
Add 7 to both sides.
3a=7-2z
The equation is in standard form.
\frac{3a}{3}=\frac{7-2z}{3}
Divide both sides by 3.
a=\frac{7-2z}{3}
Dividing by 3 undoes the multiplication by 3.
-2z=-7+3a
Swap sides so that all variable terms are on the left hand side.
-2z=3a-7
The equation is in standard form.
\frac{-2z}{-2}=\frac{3a-7}{-2}
Divide both sides by -2.
z=\frac{3a-7}{-2}
Dividing by -2 undoes the multiplication by -2.
z=\frac{7-3a}{2}
Divide -7+3a by -2.
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