Solve -6x_{1}+5x_{2}=20

$$- 6 x _ { 1 } + 5 x _ { 2 } = 20$$

Solve for x_1

$$x_{1}=\frac{5\left(x_{2}-4\right)}{6}$$

Steps for Solving Linear Equation

Subtract 5x_{2} from both sides.

$$-6x_{1}=20-5x_{2}$$

Divide both sides by -6.

$$\frac{-6x_{1}}{-6}=\frac{20-5x_{2}}{-6}$$

Dividing by -6 undoes the multiplication by -6.

$$x_{1}=\frac{20-5x_{2}}{-6}$$

Divide 20-5x_{2} by -6.

$$x_{1}=\frac{5x_{2}}{6}-\frac{10}{3}$$

Solve for x_2

$$x_{2}=\frac{6x_{1}}{5}+4$$

Steps for Solving Linear Equation

Add 6x_{1} to both sides.

$$5x_{2}=20+6x_{1}$$

The equation is in standard form.

$$5x_{2}=6x_{1}+20$$

Divide both sides by 5.

$$\frac{5x_{2}}{5}=\frac{6x_{1}+20}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$x_{2}=\frac{6x_{1}+20}{5}$$

Divide 20+6x_{1} by 5.

$$x_{2}=\frac{6x_{1}}{5}+4$$