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6\left(-x^{6}-2x^{5}+35x^{4}\right)
Factor out 6.
x^{4}\left(-x^{2}-2x+35\right)
Consider -x^{6}-2x^{5}+35x^{4}. Factor out x^{4}.
a+b=-2 ab=-35=-35
Consider -x^{2}-2x+35. Factor the expression by grouping. First, the expression needs to be rewritten as -x^{2}+ax+bx+35. To find a and b, set up a system to be solved.
1,-35 5,-7
Since ab is negative, a and b have the opposite signs. Since a+b is negative, the negative number has greater absolute value than the positive. List all such integer pairs that give product -35.
1-35=-34 5-7=-2
Calculate the sum for each pair.
a=5 b=-7
The solution is the pair that gives sum -2.
\left(-x^{2}+5x\right)+\left(-7x+35\right)
Rewrite -x^{2}-2x+35 as \left(-x^{2}+5x\right)+\left(-7x+35\right).
x\left(-x+5\right)+7\left(-x+5\right)
Factor out x in the first and 7 in the second group.
\left(-x+5\right)\left(x+7\right)
Factor out common term -x+5 by using distributive property.
6x^{4}\left(-x+5\right)\left(x+7\right)
Rewrite the complete factored expression.