Solve -6x+4geq5(x-7)

$$- 6 x + 4 \geq 5 ( x - 7 )$$

Solve for x

$$x\leq \frac{39}{11}$$

Solution Steps

Use the distributive property to multiply 5 by x-7.

$$-6x+4\geq 5x-35$$

Subtract 5x from both sides.

$$-6x+4-5x\geq -35$$

Combine -6x and -5x to get -11x.

$$-11x+4\geq -35$$

Subtract 4 from both sides.

$$-11x\geq -35-4$$

Subtract 4 from -35 to get -39.

$$-11x\geq -39$$

Divide both sides by -11. Since -11 is negative, the inequality direction is changed.

$$x\leq \frac{-39}{-11}$$

Fraction \frac{-39}{-11} can be simplified to \frac{39}{11} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{39}{11}$$