Solve -6-7x+10geq-9x-13+4x

$$- 6 - 7 x + 10 \geq - 9 x - 13 + 4 x$$

Solve for x

$$x\leq \frac{17}{2}$$

Solution Steps

Add -6 and 10 to get 4.

$$4-7x\geq -9x-13+4x$$

Combine -9x and 4x to get -5x.

$$4-7x\geq -5x-13$$

Add 5x to both sides.

$$4-7x+5x\geq -13$$

Combine -7x and 5x to get -2x.

$$4-2x\geq -13$$

Subtract 4 from both sides.

$$-2x\geq -13-4$$

Subtract 4 from -13 to get -17.

$$-2x\geq -17$$

Divide both sides by -2. Since -2 is negative, the inequality direction is changed.

$$x\leq \frac{-17}{-2}$$

Fraction \frac{-17}{-2} can be simplified to \frac{17}{2} by removing the negative sign from both the numerator and the denominator.

$$x\leq \frac{17}{2}$$