Solve -6-2=6/7(x+3)

$$- 6 - 2 = \frac { 6 } { 7 } ( x + 3 )$$

Solve for x

$$x = -\frac{37}{3} = -12\frac{1}{3} \approx -12.333333333$$

Steps for Solving Linear Equation

Subtract 2 from -6 to get -8.

$$-8=\frac{6}{7}\left(x+3\right)$$

Use the distributive property to multiply \frac{6}{7} by x+3.

$$-8=\frac{6}{7}x+\frac{6}{7}\times 3$$

Express \frac{6}{7}\times 3 as a single fraction.

$$-8=\frac{6}{7}x+\frac{6\times 3}{7}$$

Multiply 6 and 3 to get 18.

$$-8=\frac{6}{7}x+\frac{18}{7}$$

Swap sides so that all variable terms are on the left hand side.

$$\frac{6}{7}x+\frac{18}{7}=-8$$

Subtract \frac{18}{7} from both sides.

$$\frac{6}{7}x=-8-\frac{18}{7}$$

Convert -8 to fraction -\frac{56}{7}.

$$\frac{6}{7}x=-\frac{56}{7}-\frac{18}{7}$$

Since -\frac{56}{7} and \frac{18}{7} have the same denominator, subtract them by subtracting their numerators.

$$\frac{6}{7}x=\frac{-56-18}{7}$$

Subtract 18 from -56 to get -74.

$$\frac{6}{7}x=-\frac{74}{7}$$

Multiply both sides by \frac{7}{6}, the reciprocal of \frac{6}{7}.

$$x=-\frac{74}{7}\times \frac{7}{6}$$

Multiply -\frac{74}{7} times \frac{7}{6} by multiplying numerator times numerator and denominator times denominator.

$$x=\frac{-74\times 7}{7\times 6}$$

Cancel out 7 in both numerator and denominator.

$$x=\frac{-74}{6}$$

Reduce the fraction \frac{-74}{6} to lowest terms by extracting and canceling out 2.

$$x=-\frac{37}{3}$$