Solve -6(3t+2)leq6

$$- 6 ( 3 t + 2 ) \leq 6$$

Solve for t

$$t\geq -1$$

Solution Steps

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$3t+2\geq \frac{6}{-6}$$

Divide 6 by -6 to get -1.

$$3t+2\geq -1$$

Subtract 2 from both sides.

$$3t\geq -1-2$$

Subtract 2 from -1 to get -3.

$$3t\geq -3$$

Divide both sides by 3. Since 3 is positive, the inequality direction remains the same.

$$t\geq \frac{-3}{3}$$

Divide -3 by 3 to get -1.

$$t\geq -1$$