Solve -6(-3y-2/2)+12y=1

$$- 6 ( - \frac { 3 y - 2 } { 2 } ) + 12 y = 1$$

Solve for y

$$y=\frac{1}{3}\approx 0.333333333$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 2.

$$-12\left(-\frac{3y-2}{2}\right)+24y=2$$

Multiply -12 and -1 to get 12.

$$12\times \frac{3y-2}{2}+24y=2$$

Divide each term of 3y-2 by 2 to get \frac{3}{2}y-1.

$$12\left(\frac{3}{2}y-1\right)+24y=2$$

Use the distributive property to multiply 12 by \frac{3}{2}y-1.

$$12\times \frac{3}{2}y-12+24y=2$$

Express 12\times \frac{3}{2} as a single fraction.

$$\frac{12\times 3}{2}y-12+24y=2$$

Multiply 12 and 3 to get 36.

$$\frac{36}{2}y-12+24y=2$$

Divide 36 by 2 to get 18.

$$18y-12+24y=2$$

Combine 18y and 24y to get 42y.

$$42y-12=2$$

Add 12 to both sides.

$$42y=2+12$$

Add 2 and 12 to get 14.

$$42y=14$$

Divide both sides by 42.

$$y=\frac{14}{42}$$

Reduce the fraction \frac{14}{42} to lowest terms by extracting and canceling out 14.

$$y=\frac{1}{3}$$