Solve -6^3+36(x+5)+6x-9+3x=0

$$- 6 ^ { 3 } + 36 ( x + 5 ) + 6 x - 9 + 3 x = 0$$

Solve for x

$$x=1$$

Steps for Solving Linear Equation

Calculate 6 to the power of 3 and get 216.

$$-216+36\left(x+5\right)+6x-9+3x=0$$

Use the distributive property to multiply 36 by x+5.

$$-216+36x+180+6x-9+3x=0$$

Add -216 and 180 to get -36.

$$-36+36x+6x-9+3x=0$$

Combine 36x and 6x to get 42x.

$$-36+42x-9+3x=0$$

Subtract 9 from -36 to get -45.

$$-45+42x+3x=0$$

Combine 42x and 3x to get 45x.

$$-45+45x=0$$

Add 45 to both sides. Anything plus zero gives itself.

$$45x=45$$

Divide both sides by 45.

$$x=\frac{45}{45}$$

Divide 45 by 45 to get 1.

$$x=1$$