Solve -6^2-(3-7)^2-2*(-1)^3-1-2

$$- 6 ^ { 2 } - ( 3 - 7 ) ^ { 2 } - 2 \times ( - 1 ) ^ { 3 } - 1 - 2$$

Evaluate

$$-53$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$-36-\left(3-7\right)^{2}-2\left(-1\right)^{3}-1-2$$

Subtract 7 from 3 to get -4.

$$-36-\left(-4\right)^{2}-2\left(-1\right)^{3}-1-2$$

Calculate -4 to the power of 2 and get 16.

$$-36-16-2\left(-1\right)^{3}-1-2$$

Subtract 16 from -36 to get -52.

$$-52-2\left(-1\right)^{3}-1-2$$

Calculate -1 to the power of 3 and get -1.

$$-52-2\left(-1\right)-1-2$$

Multiply 2 and -1 to get -2.

$$-52-\left(-2\right)-1-2$$

The opposite of -2 is 2.

$$-52+2-1-2$$

Add -52 and 2 to get -50.

$$-50-1-2$$

Subtract 1 from -50 to get -51.

$$-51-2$$

Subtract 2 from -51 to get -53.

$$-53$$

Factor

$$-53$$