Solve -6+x<3x-326+4x

$$- 6 + x < 3 x - 326 + 4 x$$

Solve for x

$$x>\frac{160}{3}$$

Solution Steps

Combine 3x and 4x to get 7x.

$$-6+x<7x-326$$

Subtract 7x from both sides.

$$-6+x-7x<-326$$

Combine x and -7x to get -6x.

$$-6-6x<-326$$

Add 6 to both sides.

$$-6x<-326+6$$

Add -326 and 6 to get -320.

$$-6x<-320$$

Divide both sides by -6. Since -6 is negative, the inequality direction is changed.

$$x>\frac{-320}{-6}$$

Reduce the fraction \frac{-320}{-6} to lowest terms by extracting and canceling out -2.

$$x>\frac{160}{3}$$