Solve -6+(8-3)-[4+(6-3)*5-8]+3-{9-(6-4)}=

$$- 6 + ( 8 - 3 ) - [ 4 + ( 6 - 3 ) \times 5 - 8 ] + 3 - \{ 9 - ( 6 - 4 ) \} =$$

Evaluate

$$-16$$

Solution Steps

Add -6 and 8 to get 2.

$$2-3-\left(4+\left(6-3\right)\times 5-8\right)+3-\left(9-\left(6-4\right)\right)$$

Subtract 3 from 2 to get -1.

$$-1-\left(4+\left(6-3\right)\times 5-8\right)+3-\left(9-\left(6-4\right)\right)$$

Subtract 3 from 6 to get 3.

$$-1-\left(4+3\times 5-8\right)+3-\left(9-\left(6-4\right)\right)$$

Multiply 3 and 5 to get 15.

$$-1-\left(4+15-8\right)+3-\left(9-\left(6-4\right)\right)$$

Add 4 and 15 to get 19.

$$-1-\left(19-8\right)+3-\left(9-\left(6-4\right)\right)$$

Subtract 8 from 19 to get 11.

$$-1-11+3-\left(9-\left(6-4\right)\right)$$

Subtract 11 from -1 to get -12.

$$-12+3-\left(9-\left(6-4\right)\right)$$

Add -12 and 3 to get -9.

$$-9-\left(9-\left(6-4\right)\right)$$

Subtract 4 from 6 to get 2.

$$-9-\left(9-2\right)$$

Subtract 2 from 9 to get 7.

$$-9-7$$

Subtract 7 from -9 to get -16.

$$-16$$

Factor

$$-16$$