Solve for x
x=\frac{13-3y}{5}
Solve for y
y=\frac{13-5x}{3}
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-5x=3y-13
The equation is in standard form.
\frac{-5x}{-5}=\frac{3y-13}{-5}
Divide both sides by -5.
x=\frac{3y-13}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{13-3y}{5}
Divide 3y-13 by -5.
3y-13=-5x
Swap sides so that all variable terms are on the left hand side.
3y=-5x+13
Add 13 to both sides.
3y=13-5x
The equation is in standard form.
\frac{3y}{3}=\frac{13-5x}{3}
Divide both sides by 3.
y=\frac{13-5x}{3}
Dividing by 3 undoes the multiplication by 3.
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