Solve for x
x=\frac{4\left(y+10\right)}{5}
Solve for y
y=\frac{5\left(x-8\right)}{4}
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-5x=-40-4y
Subtract 4y from both sides.
-5x=-4y-40
The equation is in standard form.
\frac{-5x}{-5}=\frac{-4y-40}{-5}
Divide both sides by -5.
x=\frac{-4y-40}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{4y}{5}+8
Divide -40-4y by -5.
4y=-40+5x
Add 5x to both sides.
4y=5x-40
The equation is in standard form.
\frac{4y}{4}=\frac{5x-40}{4}
Divide both sides by 4.
y=\frac{5x-40}{4}
Dividing by 4 undoes the multiplication by 4.
y=\frac{5x}{4}-10
Divide -40+5x by 4.
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