Solve for x
x=\frac{3\left(y+3\right)}{5}
Solve for y
y=\frac{5x}{3}-3
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-5x=-9-3y
Subtract 3y from both sides.
-5x=-3y-9
The equation is in standard form.
\frac{-5x}{-5}=\frac{-3y-9}{-5}
Divide both sides by -5.
x=\frac{-3y-9}{-5}
Dividing by -5 undoes the multiplication by -5.
x=\frac{3y+9}{5}
Divide -9-3y by -5.
3y=-9+5x
Add 5x to both sides.
3y=5x-9
The equation is in standard form.
\frac{3y}{3}=\frac{5x-9}{3}
Divide both sides by 3.
y=\frac{5x-9}{3}
Dividing by 3 undoes the multiplication by 3.
y=\frac{5x}{3}-3
Divide -9+5x by 3.
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