Solve for t
t=-\frac{5v}{2}-19
Solve for v
v=\frac{-2t-38}{5}
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-2t=38+5v
Add 5v to both sides.
-2t=5v+38
The equation is in standard form.
\frac{-2t}{-2}=\frac{5v+38}{-2}
Divide both sides by -2.
t=\frac{5v+38}{-2}
Dividing by -2 undoes the multiplication by -2.
t=-\frac{5v}{2}-19
Divide 38+5v by -2.
-5v=38+2t
Add 2t to both sides.
-5v=2t+38
The equation is in standard form.
\frac{-5v}{-5}=\frac{2t+38}{-5}
Divide both sides by -5.
v=\frac{2t+38}{-5}
Dividing by -5 undoes the multiplication by -5.
v=\frac{-2t-38}{5}
Divide 38+2t by -5.
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