Solve -5ax+4a^2-a=0

$$- 5 a x + 4 a ^ { 2 } - a = 0$$

Solve for x (complex solution)

$$\left\{\begin{matrix}\\x=\frac{4a-1}{5}\text{, }&\text{unconditionally}\\x\in \mathrm{C}\text{, }&a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 4a^{2} from both sides. Anything subtracted from zero gives its negation.

$$-5ax-a=-4a^{2}$$

Add a to both sides.

$$-5ax=-4a^{2}+a$$

The equation is in standard form.

$$\left(-5a\right)x=a-4a^{2}$$

Divide both sides by -5a.

$$\frac{\left(-5a\right)x}{-5a}=\frac{a\left(1-4a\right)}{-5a}$$

Dividing by -5a undoes the multiplication by -5a.

$$x=\frac{a\left(1-4a\right)}{-5a}$$

Divide a\left(1-4a\right) by -5a.

$$x=\frac{4a-1}{5}$$

Solve for x

$$\left\{\begin{matrix}\\x=\frac{4a-1}{5}\text{, }&\text{unconditionally}\\x\in \mathrm{R}\text{, }&a=0\end{matrix}\right.$$

Steps for Solving Linear Equation

Subtract 4a^{2} from both sides. Anything subtracted from zero gives its negation.

$$-5ax-a=-4a^{2}$$

Add a to both sides.

$$-5ax=-4a^{2}+a$$

The equation is in standard form.

$$\left(-5a\right)x=a-4a^{2}$$

Divide both sides by -5a.

$$\frac{\left(-5a\right)x}{-5a}=\frac{a\left(1-4a\right)}{-5a}$$

Dividing by -5a undoes the multiplication by -5a.

$$x=\frac{a\left(1-4a\right)}{-5a}$$

Divide a\left(1-4a\right) by -5a.

$$x=\frac{4a-1}{5}$$

Solve for a

$$a=\frac{5x+1}{4}$$

$$a=0$$