Solve -5(t+2)=-5ct

$$- 5 ( t + 2 ) = - 5 c t$$

Solve for c

$$c=\frac{t+2}{t}$$

$$t\neq 0$$

Steps for Solving Linear Equation

Cancel out -5 on both sides.

$$t+2=ct$$

Swap sides so that all variable terms are on the left hand side.

$$ct=t+2$$

The equation is in standard form.

$$tc=t+2$$

Divide both sides by t.

$$\frac{tc}{t}=\frac{t+2}{t}$$

Dividing by t undoes the multiplication by t.

$$c=\frac{t+2}{t}$$

Solve for t

$$t=\frac{2}{c-1}$$

$$c\neq 1$$

Steps for Solving Linear Equation

Cancel out -5 on both sides.

$$t+2=ct$$

Subtract ct from both sides.

$$t+2-ct=0$$

Subtract 2 from both sides. Anything subtracted from zero gives its negation.

$$t-ct=-2$$

Combine all terms containing t.

$$\left(1-c\right)t=-2$$

Divide both sides by 1-c.

$$\frac{\left(1-c\right)t}{1-c}=-\frac{2}{1-c}$$

Dividing by 1-c undoes the multiplication by 1-c.

$$t=-\frac{2}{1-c}$$