Solve -53/8+45/6-(-21/4)

$$- 5 \frac { 3 } { 8 } + 4 \frac { 5 } { 6 } - ( - 2 \frac { 1 } { 4 } )$$

Evaluate

$$\frac{41}{24}\approx 1.708333333$$

Solution Steps

Multiply 5 and 8 to get 40.

$$-\frac{40+3}{8}+\frac{4\times 6+5}{6}-\left(-\frac{2\times 4+1}{4}\right)$$

Add 40 and 3 to get 43.

$$-\frac{43}{8}+\frac{4\times 6+5}{6}-\left(-\frac{2\times 4+1}{4}\right)$$

Multiply 4 and 6 to get 24.

$$-\frac{43}{8}+\frac{24+5}{6}-\left(-\frac{2\times 4+1}{4}\right)$$

Add 24 and 5 to get 29.

$$-\frac{43}{8}+\frac{29}{6}-\left(-\frac{2\times 4+1}{4}\right)$$

Least common multiple of 8 and 6 is 24. Convert -\frac{43}{8} and \frac{29}{6} to fractions with denominator 24.

$$-\frac{129}{24}+\frac{116}{24}-\left(-\frac{2\times 4+1}{4}\right)$$

Since -\frac{129}{24} and \frac{116}{24} have the same denominator, add them by adding their numerators.

$$\frac{-129+116}{24}-\left(-\frac{2\times 4+1}{4}\right)$$

Add -129 and 116 to get -13.

$$-\frac{13}{24}-\left(-\frac{2\times 4+1}{4}\right)$$

Multiply 2 and 4 to get 8.

$$-\frac{13}{24}-\left(-\frac{8+1}{4}\right)$$

Add 8 and 1 to get 9.

$$-\frac{13}{24}-\left(-\frac{9}{4}\right)$$

The opposite of -\frac{9}{4} is \frac{9}{4}.

$$-\frac{13}{24}+\frac{9}{4}$$

Least common multiple of 24 and 4 is 24. Convert -\frac{13}{24} and \frac{9}{4} to fractions with denominator 24.

$$-\frac{13}{24}+\frac{54}{24}$$

Since -\frac{13}{24} and \frac{54}{24} have the same denominator, add them by adding their numerators.

$$\frac{-13+54}{24}$$

Add -13 and 54 to get 41.

$$\frac{41}{24}$$

Factor

$$\frac{41}{2 ^ {3} \cdot 3} = 1\frac{17}{24} = 1.7083333333333333$$