Solve for b (complex solution)
\left\{\begin{matrix}b=-\frac{4z+c-1}{z}\text{, }&z\neq 0\\b\in \mathrm{C}\text{, }&z=0\text{ and }c=1\end{matrix}\right.
Solve for b
\left\{\begin{matrix}b=-\frac{4z+c-1}{z}\text{, }&z\neq 0\\b\in \mathrm{R}\text{, }&z=0\text{ and }c=1\end{matrix}\right.
Solve for c
c=1-4z-bz
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bz+c=-4z+1
Swap sides so that all variable terms are on the left hand side.
bz=-4z+1-c
Subtract c from both sides.
zb=1-c-4z
The equation is in standard form.
\frac{zb}{z}=\frac{1-c-4z}{z}
Divide both sides by z.
b=\frac{1-c-4z}{z}
Dividing by z undoes the multiplication by z.
bz+c=-4z+1
Swap sides so that all variable terms are on the left hand side.
bz=-4z+1-c
Subtract c from both sides.
zb=1-c-4z
The equation is in standard form.
\frac{zb}{z}=\frac{1-c-4z}{z}
Divide both sides by z.
b=\frac{1-c-4z}{z}
Dividing by z undoes the multiplication by z.
bz+c=-4z+1
Swap sides so that all variable terms are on the left hand side.
c=-4z+1-bz
Subtract bz from both sides.
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