Solve for x
x=-2y-\frac{3}{2}
Solve for y
y=-\frac{x}{2}-\frac{3}{4}
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-2x-3=4y
Add 4y to both sides. Anything plus zero gives itself.
-2x=4y+3
Add 3 to both sides.
\frac{-2x}{-2}=\frac{4y+3}{-2}
Divide both sides by -2.
x=\frac{4y+3}{-2}
Dividing by -2 undoes the multiplication by -2.
x=-2y-\frac{3}{2}
Divide 4y+3 by -2.
-4y-3=2x
Add 2x to both sides. Anything plus zero gives itself.
-4y=2x+3
Add 3 to both sides.
\frac{-4y}{-4}=\frac{2x+3}{-4}
Divide both sides by -4.
y=\frac{2x+3}{-4}
Dividing by -4 undoes the multiplication by -4.
y=-\frac{x}{2}-\frac{3}{4}
Divide 2x+3 by -4.
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Limits
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