Solve for x
x=\frac{17-3y}{4}
Solve for y
y=\frac{17-4x}{3}
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-4x+17=3y
Add 3y to both sides. Anything plus zero gives itself.
-4x=3y-17
Subtract 17 from both sides.
\frac{-4x}{-4}=\frac{3y-17}{-4}
Divide both sides by -4.
x=\frac{3y-17}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{17-3y}{4}
Divide 3y-17 by -4.
-3y+17=4x
Add 4x to both sides. Anything plus zero gives itself.
-3y=4x-17
Subtract 17 from both sides.
\frac{-3y}{-3}=\frac{4x-17}{-3}
Divide both sides by -3.
y=\frac{4x-17}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{17-4x}{3}
Divide 4x-17 by -3.
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