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-4x^{2}-48x-208=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-48\right)±\sqrt{\left(-48\right)^{2}-4\left(-4\right)\left(-208\right)}}{2\left(-4\right)}
This equation is in standard form: ax^{2}+bx+c=0. Substitute -4 for a, -48 for b, and -208 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-48\right)±\sqrt{2304-4\left(-4\right)\left(-208\right)}}{2\left(-4\right)}
Square -48.
x=\frac{-\left(-48\right)±\sqrt{2304+16\left(-208\right)}}{2\left(-4\right)}
Multiply -4 times -4.
x=\frac{-\left(-48\right)±\sqrt{2304-3328}}{2\left(-4\right)}
Multiply 16 times -208.
x=\frac{-\left(-48\right)±\sqrt{-1024}}{2\left(-4\right)}
Add 2304 to -3328.
x=\frac{-\left(-48\right)±32i}{2\left(-4\right)}
Take the square root of -1024.
x=\frac{48±32i}{2\left(-4\right)}
The opposite of -48 is 48.
x=\frac{48±32i}{-8}
Multiply 2 times -4.
x=\frac{48+32i}{-8}
Now solve the equation x=\frac{48±32i}{-8} when ± is plus. Add 48 to 32i.
x=-6-4i
Divide 48+32i by -8.
x=\frac{48-32i}{-8}
Now solve the equation x=\frac{48±32i}{-8} when ± is minus. Subtract 32i from 48.
x=-6+4i
Divide 48-32i by -8.
x=-6-4i x=-6+4i
The equation is now solved.
-4x^{2}-48x-208=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
-4x^{2}-48x-208-\left(-208\right)=-\left(-208\right)
Add 208 to both sides of the equation.
-4x^{2}-48x=-\left(-208\right)
Subtracting -208 from itself leaves 0.
-4x^{2}-48x=208
Subtract -208 from 0.
\frac{-4x^{2}-48x}{-4}=\frac{208}{-4}
Divide both sides by -4.
x^{2}+\left(-\frac{48}{-4}\right)x=\frac{208}{-4}
Dividing by -4 undoes the multiplication by -4.
x^{2}+12x=\frac{208}{-4}
Divide -48 by -4.
x^{2}+12x=-52
Divide 208 by -4.
x^{2}+12x+6^{2}=-52+6^{2}
Divide 12, the coefficient of the x term, by 2 to get 6. Then add the square of 6 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+12x+36=-52+36
Square 6.
x^{2}+12x+36=-16
Add -52 to 36.
\left(x+6\right)^{2}=-16
Factor x^{2}+12x+36. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+6\right)^{2}}=\sqrt{-16}
Take the square root of both sides of the equation.
x+6=4i x+6=-4i
Simplify.
x=-6+4i x=-6-4i
Subtract 6 from both sides of the equation.
x ^ 2 +12x +52 = 0
Quadratic equations such as this one can be solved by a new direct factoring method that does not require guess work. To use the direct factoring method, the equation must be in the form x^2+Bx+C=0.
r + s = -12 rs = 52
Let r and s be the factors for the quadratic equation such that x^2+Bx+C=(x−r)(x−s) where sum of factors (r+s)=−B and the product of factors rs = C
r = -6 - u s = -6 + u
Two numbers r and s sum up to -12 exactly when the average of the two numbers is \frac{1}{2}*-12 = -6. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. The values of r and s are equidistant from the center by an unknown quantity u. Express r and s with respect to variable u. <div style='padding: 8px'><img src='https://opalmath.azureedge.net/customsolver/quadraticgraph.png' style='width: 100%;max-width: 700px' /></div>
(-6 - u) (-6 + u) = 52
To solve for unknown quantity u, substitute these in the product equation rs = 52
36 - u^2 = 52
Simplify by expanding (a -b) (a + b) = a^2 – b^2
-u^2 = 52-36 = 16
Simplify the expression by subtracting 36 on both sides
u^2 = -16 u = \pm\sqrt{-16} = \pm 4i
Simplify the expression by multiplying -1 on both sides and take the square root to obtain the value of unknown variable u
r =-6 - 4i s = -6 + 4i
The factors r and s are the solutions to the quadratic equation. Substitute the value of u to compute the r and s.