Solve for x
x=\frac{3y}{4}-1
Solve for y
y=\frac{4\left(x+1\right)}{3}
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-4x=4-3y
The equation is in standard form.
\frac{-4x}{-4}=\frac{4-3y}{-4}
Divide both sides by -4.
x=\frac{4-3y}{-4}
Dividing by -4 undoes the multiplication by -4.
x=\frac{3y}{4}-1
Divide 4-3y by -4.
4-3y=-4x
Swap sides so that all variable terms are on the left hand side.
-3y=-4x-4
Subtract 4 from both sides.
\frac{-3y}{-3}=\frac{-4x-4}{-3}
Divide both sides by -3.
y=\frac{-4x-4}{-3}
Dividing by -3 undoes the multiplication by -3.
y=\frac{4x+4}{3}
Divide -4x-4 by -3.
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\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
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Limits
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